What are the solutions to the equation 4x^2-3x-10=0 ?

The solutions to the equation 4x^2-3x-10=0 are x=2,x=-5/4

Find the zeros of 4x^2-3x-10=0

The zeros of 4x^2-3x-10=0 are x=2,x=-5/4

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4 x^{2} - 3 x - 10 = 0

x = 2, x = - \frac{5}{4}

Decimal Notation

x = 2, x = - 1.25

Solution steps

4 x^{2} - 3 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 4 ( - 10 )}{2 \cdot 4}

(- 3)^{2} - 4 \cdot 4 (- 10) = 13

x_{1, 2} = \frac{- ( - 3 ) \pm 13}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 13}{2 \cdot 4}, x_{2} = \frac{- ( - 3 ) - 13}{2 \cdot 4}

x = \frac{- ( - 3 ) + 13}{2 \cdot 4} : 2

x = \frac{- ( - 3 ) - 13}{2 \cdot 4} : - \frac{5}{4}

The solutions to the quadratic equation are:

x = 2, x = - \frac{5}{4}

3 x + 4 \leq 8 x - 2

- \frac{1}{2} - \frac{2}{5}

(2 x + 1)^{2} = 27

2 (3 x + 5) = 22

\frac{3 f ^{4} g ^{3} \cdot 8 f g ^{4}}{( 6 f ^{2} g ^{3} ) ^{2}}

What are the solutions to the equation 4x^2-3x-10=0 ?
The solutions to the equation 4x^2-3x-10=0 are x=2,x=-5/4
Find the zeros of 4x^2-3x-10=0
The zeros of 4x^2-3x-10=0 are x=2,x=-5/4