What are the solutions to the equation 100x^2+1=12x ?

The solutions to the equation 100x^2+1=12x are x= 3/50+i 2/25 ,x= 3/50-i 2/25

Find the zeros of 100x^2+1=12x

The zeros of 100x^2+1=12x are x= 3/50+i 2/25 ,x= 3/50-i 2/25

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100 x^{2} + 1 = 12 x

x = \frac{3}{50} + i \frac{2}{25}, x = \frac{3}{50} - i \frac{2}{25}

Solution steps

100 x^{2} + 1 = 12 x

Move

12 x

to the left side

100 x^{2} + 1 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

100 x^{2} - 12 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 100 \cdot 1}{2 \cdot 100}

Simplify

(- 12)^{2} - 4 \cdot 100 \cdot 1 : 16 i

x_{1, 2} = \frac{- ( - 12 ) \pm 16 i}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 16 i}{2 \cdot 100}, x_{2} = \frac{- ( - 12 ) - 16 i}{2 \cdot 100}

x = \frac{- ( - 12 ) + 16 i}{2 \cdot 100} : \frac{3}{50} + i \frac{2}{25}

x = \frac{- ( - 12 ) - 16 i}{2 \cdot 100} : \frac{3}{50} - i \frac{2}{25}

The solutions to the quadratic equation are:

x = \frac{3}{50} + i \frac{2}{25}, x = \frac{3}{50} - i \frac{2}{25}

\frac{5}{4} - \frac{27}{2}

- 16 x^{2} + 64 x + 80

27 \cdot 6

x^{2} + 7 x - 18

x (x - 1)^{2} < 0

What are the solutions to the equation 100x^2+1=12x ?
The solutions to the equation 100x^2+1=12x are x= 3/50+i 2/25 ,x= 3/50-i 2/25
Find the zeros of 100x^2+1=12x
The zeros of 100x^2+1=12x are x= 3/50+i 2/25 ,x= 3/50-i 2/25