What are the solutions to the equation (x-8)(x+5)=0 ?

The solutions to the equation (x-8)(x+5)=0 are x=8,x=-5

Find the zeros of (x-8)(x+5)=0

The zeros of (x-8)(x+5)=0 are x=8,x=-5

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(x - 8) (x + 5) = 0

x = 8, x = - 5

Solution steps

(x - 8) (x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 8 = 0 or x + 5 = 0

Solve

x - 8 = 0 : x = 8

Solve

x + 5 = 0 : x = - 5

The solutions to the quadratic equation are:

x = 8, x = - 5

\frac{5 + 6 i}{5 - 6 i}

\frac{9}{2} + \frac{11}{4}

(\frac{5 a ^{- 7} b ^{2}}{a b ^{- 6}})^{- 3}

- 3 (y + 3) = 2 y + 3

\frac{m}{3} - 2 = 2

What are the solutions to the equation (x-8)(x+5)=0 ?
The solutions to the equation (x-8)(x+5)=0 are x=8,x=-5
Find the zeros of (x-8)(x+5)=0
The zeros of (x-8)(x+5)=0 are x=8,x=-5