What is factor 10x^2+27x+5 ?

The solution to factor 10x^2+27x+5 is (5x+1)(2x+5)

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factor 10x^2+27x+5

factor

10 x^{2} + 27 x + 5

(5 x + 1) (2 x + 5)

Solution steps

10 x^{2} + 27 x + 5

Break the expression into groups

= (10 x^{2} + 2 x) + (25 x + 5)

Factor out

2 x

from

10 x^{2} + 2 x : 2 x (5 x + 1)

Factor out

5

from

25 x + 5 : 5 (5 x + 1)

= 2 x (5 x + 1) + 5 (5 x + 1)

Factor out common term

5 x + 1

= (5 x + 1) (2 x + 5)

3 (s + 1) - 8 = 6 s (2 - 4)

(x)^{2} + (73)^{2} = (2 x)^{2}

\frac{8 b ^{5}}{64 b ^{4}}

(x - 1) (x + 3) = 0

49 b^{2} - 9