What are the solutions to the equation b^2-9=0 ?

The solutions to the equation b^2-9=0 are b=3,b=-3

Find the zeros of b^2-9=0

The zeros of b^2-9=0 are b=3,b=-3

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b^{2} - 9 = 0

b = 3, b = - 3

Solution steps

b^{2} - 9 = 0

Move

9

to the right side

b^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 9, b = - 9

9 = 3

- 9 = - 3

b = 3, b = - 3

12 x^{2} - 7 x y - 10 y^{2}

x^{2} y + x^{4} y^{4}

\frac{( ( 1.17 ) ( 1.03 ) ^{2} )}{2} + C = 5.1

\frac{( 1 - x ^{2} ) ( 2 - x )}{x ^{2} + 5 x + 6} \leq 0

(x^{2} y)^{4}

What are the solutions to the equation b^2-9=0 ?
The solutions to the equation b^2-9=0 are b=3,b=-3
Find the zeros of b^2-9=0
The zeros of b^2-9=0 are b=3,b=-3