What are the solutions to the equation r^2+15=0 ?

The solutions to the equation r^2+15=0 are r=sqrt(15)i,r=-sqrt(15)i

Find the zeros of r^2+15=0

The zeros of r^2+15=0 are r=sqrt(15)i,r=-sqrt(15)i

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r^{2} + 15 = 0

r = 15 i, r = - 15 i

Solution steps

r^{2} + 15 = 0

Move

15

to the right side

r^{2} = - 15

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = - 15, r = - - 15

- 15 = 15 i

- - 15 = - 15 i

r = 15 i, r = - 15 i

(2)^{2} + 2

\frac{d - 3}{10} \geq \frac{2 d + 3}{5} + \frac{d + 3}{3}

z^{5} \cdot z^{6}

∣ - 2 - 5 x ∣ = \frac{7}{4}

64 - y^{4}

What are the solutions to the equation r^2+15=0 ?
The solutions to the equation r^2+15=0 are r=sqrt(15)i,r=-sqrt(15)i
Find the zeros of r^2+15=0
The zeros of r^2+15=0 are r=sqrt(15)i,r=-sqrt(15)i