What is the answer to (x-4)/4-(5x+3}{32}= 7/16-\frac{5x)/8 ?

The answer to (x-4)/4-(5x+3}{32}= 7/16-\frac{5x)/8 is x= 49/23

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(x-4)/4-(5x+3}{32}= 7/16-\frac{5x)/8

\frac{x - 4}{4} - \frac{5 x + 3}{32} = \frac{7}{16} - \frac{5 x}{8}

x = \frac{49}{23}

Decimal Notation

x = 2.13043 \dots

Solution steps

\frac{x - 4}{4} - \frac{5 x + 3}{32} = \frac{7}{16} - \frac{5 x}{8}

Move

\frac{5 x}{8}

to the left side

\frac{23 x - 35}{32} = \frac{7}{16}

Multiply both sides by

32

23 x - 35 = 14

Move

35

to the right side

23 x = 49

Divide both sides by

23

x = \frac{49}{23}

∣ 3 - 4 x ∣ \geq 13

x (3 x - 12) (4 x - 32) \geq 0

x^{3} - 2 x^{2} - x + 2 > 0

x + 6 (0.56254 - 5.2) + 38 (2.61845 - 5.2) = 0

\frac{- 2 - 10}{e ^{2}}

What is the answer to (x-4)/4-(5x+3}{32}= 7/16-\frac{5x)/8 ?
The answer to (x-4)/4-(5x+3}{32}= 7/16-\frac{5x)/8 is x= 49/23
Solve for x: (x-4)/4-(5x+3}{32}= 7/16-\frac{5x)/8
The solution is x= 49/23