What is factor 2n^4+8n^3+11n^2+6n+1 ?

The solution to factor 2n^4+8n^3+11n^2+6n+1 is (n+1)^2(2n^2+4n+1)

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factor 2n^4+8n^3+11n^2+6n+1

factor

2 n^{4} + 8 n^{3} + 11 n^{2} + 6 n + 1

(n + 1)^{2} (2 n^{2} + 4 n + 1)

Solution steps

2 n^{4} + 8 n^{3} + 11 n^{2} + 6 n + 1

Use the rational root theorem

= (n + 1) \frac{2 n ^{4} + 8 n ^{3} + 11 n ^{2} + 6 n + 1}{n + 1}

\frac{2 n ^{4} + 8 n ^{3} + 11 n ^{2} + 6 n + 1}{n + 1} = 2 n^{3} + 6 n^{2} + 5 n + 1

= (n + 1) (2 n^{3} + 6 n^{2} + 5 n + 1)

Factor

2 n^{3} + 6 n^{2} + 5 n + 1 : (n + 1) (2 n^{2} + 4 n + 1)

= (n + 1) (n + 1) (2 n^{2} + 4 n + 1)

Apply exponent rule:

aa = a^{2}

(n + 1) (n + 1) = (n + 1)^{2}

= (n + 1)^{2} (2 n^{2} + 4 n + 1)

Y = 0.00007 \cdot 1. 2^{2} - 0.003 \cdot 1.2 + 0.0063

0 + (9.76 - \frac{12.5}{103} (0)) 0.5

x^{2} - x - 5 < 3

n^{2} + 77 = 0

5 x + 4 = 3 x - 4

What is factor 2n^4+8n^3+11n^2+6n+1 ?
The solution to factor 2n^4+8n^3+11n^2+6n+1 is (n+1)^2(2n^2+4n+1)