What are the solutions to the equation x^2+6x+11=0 ?

The solutions to the equation x^2+6x+11=0 are x=-3+sqrt(2)i,x=-3-sqrt(2)i

Find the zeros of x^2+6x+11=0

The zeros of x^2+6x+11=0 are x=-3+sqrt(2)i,x=-3-sqrt(2)i

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x^{2} + 6 x + 11 = 0

x = - 3 + 2 i, x = - 3 - 2 i

Solution steps

x^{2} + 6 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 11}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 11 : 22 i

x_{1, 2} = \frac{- 6 \pm 2 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 2 i}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 2 i}{2 \cdot 1}

x = \frac{- 6 + 2 2 i}{2 \cdot 1} : - 3 + 2 i

x = \frac{- 6 - 2 2 i}{2 \cdot 1} : - 3 - 2 i

The solutions to the quadratic equation are:

x = - 3 + 2 i, x = - 3 - 2 i

(\frac{1}{3})^{4} (\frac{- 1}{2})^{- 4} (\frac{1}{9})^{3}

p^{2} - 6 - q \cdot (p^{2} - 6)

\frac{12}{5} = 6 x

7 (2 e - 1) - 11 = 6 + 6 e

(3 n - 2) (4 n + 1) = 0

What are the solutions to the equation x^2+6x+11=0 ?
The solutions to the equation x^2+6x+11=0 are x=-3+sqrt(2)i,x=-3-sqrt(2)i
Find the zeros of x^2+6x+11=0
The zeros of x^2+6x+11=0 are x=-3+sqrt(2)i,x=-3-sqrt(2)i