What are the solutions to the equation r^2-6r+4=0 ?

The solutions to the equation r^2-6r+4=0 are r=3+sqrt(5),r=3-sqrt(5)

Find the zeros of r^2-6r+4=0

The zeros of r^2-6r+4=0 are r=3+sqrt(5),r=3-sqrt(5)

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r^{2} - 6 r + 4 = 0

r = 3 + 5, r = 3 - 5

Decimal Notation

r = 5.23606 \dots, r = 0.76393 \dots

Solution steps

r^{2} - 6 r + 4 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 4 = 25

r_{1, 2} = \frac{- ( - 6 ) \pm 2 5}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 6 ) + 2 5}{2 \cdot 1}, r_{2} = \frac{- ( - 6 ) - 2 5}{2 \cdot 1}

r = \frac{- ( - 6 ) + 2 5}{2 \cdot 1} : 3 + 5

r = \frac{- ( - 6 ) - 2 5}{2 \cdot 1} : 3 - 5

The solutions to the quadratic equation are:

r = 3 + 5, r = 3 - 5

9 a^{2} - 6 ab + b^{2}

2 x^{2} - 5 x

\frac{x ^{2} y ^{5}}{x y ^{4}}

6 x^{2} + 72 x + 210

\frac{1}{4} - \frac{13}{8} x = - \frac{6}{5} x + \frac{11}{6}

What are the solutions to the equation r^2-6r+4=0 ?
The solutions to the equation r^2-6r+4=0 are r=3+sqrt(5),r=3-sqrt(5)
Find the zeros of r^2-6r+4=0
The zeros of r^2-6r+4=0 are r=3+sqrt(5),r=3-sqrt(5)