What are the solutions to the equation ((x-4)/2)^2-2((x-4)/2)+65=0 ?

The solutions to the equation ((x-4)/2)^2-2((x-4)/2)+65=0 are x=6+16i,x=6-16i

Find the zeros of ((x-4)/2)^2-2((x-4)/2)+65=0

The zeros of ((x-4)/2)^2-2((x-4)/2)+65=0 are x=6+16i,x=6-16i

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(\frac{x - 4}{2})^{2} - 2 (\frac{x - 4}{2}) + 65 = 0

x = 6 + 16 i, x = 6 - 16 i

Solution steps

(\frac{x - 4}{2})^{2} - 2 (\frac{x - 4}{2}) + 65 = 0

Expand

(\frac{x - 4}{2})^{2} - 2 (\frac{x - 4}{2}) + 65 : \frac{x ^{2}}{4} - 3 x + 73

\frac{x ^{2}}{4} - 3 x + 73 = 0

Write in the standard form

a x^{2} + b x + c = 0

\frac{1 \cdot x ^{2}}{4} - 3 x + 73 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot \frac{1}{4} \cdot 73}{2 \cdot \frac{1}{4}}

Simplify

(- 3)^{2} - 4 \cdot \frac{1}{4} \cdot 73 : 8 i

x_{1, 2} = \frac{- ( - 3 ) \pm 8 i}{2 \cdot \frac{1}{4}}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 8 i}{2 \cdot \frac{1}{4}}, x_{2} = \frac{- ( - 3 ) - 8 i}{2 \cdot \frac{1}{4}}

x = \frac{- ( - 3 ) + 8 i}{2 \frac{1}{4}} : 6 + 16 i

x = \frac{- ( - 3 ) - 8 i}{2 \frac{1}{4}} : 6 - 16 i

The solutions to the quadratic equation are:

x = 6 + 16 i, x = 6 - 16 i

3 m^{3} + 6 m^{2}

36 x^{2} - 4

10 q r - 20 q - 21 r + 42

- 7 - 5

∣ x - 2 ∣ > - 5

What are the solutions to the equation ((x-4)/2)^2-2((x-4)/2)+65=0 ?
The solutions to the equation ((x-4)/2)^2-2((x-4)/2)+65=0 are x=6+16i,x=6-16i
Find the zeros of ((x-4)/2)^2-2((x-4)/2)+65=0
The zeros of ((x-4)/2)^2-2((x-4)/2)+65=0 are x=6+16i,x=6-16i