What is the answer to (3x-1)/2-(2x+3)/3 =1 ?

The answer to (3x-1)/2-(2x+3)/3 =1 is x=3

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(3x-1)/2-(2x+3)/3 =1

\frac{3 x - 1}{2} - \frac{2 x + 3}{3} = 1

x = 3

Solution steps

\frac{3 x - 1}{2} - \frac{2 x + 3}{3} = 1

Multiply by LCM

3 (3 x - 1) - 2 (2 x + 3) = 6

Expand

3 (3 x - 1) - 2 (2 x + 3) : 5 x - 9

5 x - 9 = 6

Move

9

to the right side

5 x = 15

Divide both sides by

5

x = 3

3 x - 6 = 15

3 x^{2} + 3 x y + x + y

z = - 2 + 3 i

64 + a^{3}

(5^{\frac{1}{3}} \cdot x^{\frac{1}{4}})^{3}

What is the answer to (3x-1)/2-(2x+3)/3 =1 ?
The answer to (3x-1)/2-(2x+3)/3 =1 is x=3
Solve for x: (3x-1)/2-(2x+3)/3 =1
The solution is x=3