What are the solutions to the equation (2x-5)^2=11 ?

The solutions to the equation (2x-5)^2=11 are x=(sqrt(11)+5)/2 ,x=(-sqrt(11)+5)/2

Find the zeros of (2x-5)^2=11

The zeros of (2x-5)^2=11 are x=(sqrt(11)+5)/2 ,x=(-sqrt(11)+5)/2

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(2 x - 5)^{2} = 11

x = \frac{11 + 5}{2}, x = \frac{- 11 + 5}{2}

Decimal Notation

x = 4.15831 \dots, x = 0.84168 \dots

Solution steps

(2 x - 5)^{2} = 11

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 5 = 11 : x = \frac{11 + 5}{2}

Solve

2 x - 5 = - 11 : x = \frac{- 11 + 5}{2}

The solutions to the quadratic equation are:

x = \frac{11 + 5}{2}, x = \frac{- 11 + 5}{2}

r^{2} + 3 r - 2 = 0

(- 0.008)^{\frac{2}{3}}

x^{6} - 6 x^{3} y + 9 y^{2}

16 x^{8} + 8 x^{4} + 1

\frac{x ^{5} y ^{2}}{x ^{4} y ^{0}}

What are the solutions to the equation (2x-5)^2=11 ?
The solutions to the equation (2x-5)^2=11 are x=(sqrt(11)+5)/2 ,x=(-sqrt(11)+5)/2
Find the zeros of (2x-5)^2=11
The zeros of (2x-5)^2=11 are x=(sqrt(11)+5)/2 ,x=(-sqrt(11)+5)/2