What is 4(2x-3)(2x+9)<= 0 ?

The solution to 4(2x-3)(2x+9)<= 0 is -9/2 <= x<= 3/2

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4(2x-3)(2x+9)<= 0

4 (2 x - 3) (2 x + 9) \leq 0

- \frac{9}{2} \leq x \leq \frac{3}{2}

Interval Notation

[- \frac{9}{2}, \frac{3}{2}]

Decimal Notation

- 4.5 \leq x \leq 1.5

Solution steps

4 (2 x - 3) (2 x + 9) \leq 0

Rewrite in standard form

4 x^{2} + 12 x - 27 \leq 0

Factor

4 x^{2} + 12 x - 27 : (2 x - 3) (2 x + 9)

(2 x - 3) (2 x + 9) \leq 0

Identify the intervals

- \frac{9}{2} \leq x \leq \frac{3}{2}

10 (23 + 7) = 100 x + 100 x

\frac{7 !}{4 !}

x^{3} - 4 x^{2} + 4 x

2 x^{2} = 8 x + 3

k + 10 = 27

What is 4(2x-3)(2x+9)<= 0 ?
The solution to 4(2x-3)(2x+9)<= 0 is -9/2 <= x<= 3/2