What is (5b^3+9b+4)-(9b-4) ?

The solution to (5b^3+9b+4)-(9b-4) is 5b^3+8

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simplify (5b^3+9b+4)-(9b-4)

simplify

(5 b^{3} + 9 b + 4) - (9 b - 4)

5 b^{3} + 8

Solution steps

(5 b^{3} + 9 b + 4) - (9 b - 4)

Apply rule:

(a) = a

(5 b^{3} + 9 b + 4) = 5 b^{3} + 9 b + 4

= 5 b^{3} + 9 b + 4 - (9 b - 4)

Apply the distributive law:

- (a - b) = - a + b

- (9 b - 4) = - 9 b + 4

= 5 b^{3} + 9 b + 4 - 9 b + 4

Group like terms

= 5 b^{3} + 9 b - 9 b + 4 + 4

Add similar elements:

9 b - 9 b = 0

= 5 b^{3} + 4 + 4

Add the numbers:

4 + 4 = 8

= 5 b^{3} + 8

y^{2} + y - 2 = 0

x^{2} + 2

\frac{m}{- 2} > 2

3 (1 + 2 x) = 6 x + 1

\frac{57.66226}{12 ( 0.0001 )} \geq n^{2}