What is (1/5 x^3-8y^2-6)-(y^2-5x^3+10) ?

The solution to (1/5 x^3-8y^2-6)-(y^2-5x^3+10) is 5x^3-9y^2+1/5 x^3-16

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simplify (1/5 x^3-8y^2-6)-(y^2-5x^3+10)

simplify

(\frac{1}{5} x^{3} - 8 y^{2} - 6) - (y^{2} - 5 x^{3} + 10)

5 x^{3} - 9 y^{2} + \frac{1}{5} x^{3} - 16

Solution steps

(\frac{1}{5} x^{3} - 8 y^{2} - 6) - (y^{2} - 5 x^{3} + 10)

Apply rule:

(a) = a

(\frac{1}{5} x^{3} - 8 y^{2} - 6) = \frac{1}{5} x^{3} - 8 y^{2} - 6

= \frac{1}{5} x^{3} - 8 y^{2} - 6 - (y^{2} - 5 x^{3} + 10)

Apply the distributive law:

- (a - b) = - a + b

- (y^{2} - 5 x^{3} + 10) = - y^{2} + 5 x^{3} - 10

= \frac{1}{5} x^{3} - 8 y^{2} - 6 - y^{2} + 5 x^{3} - 10

Group like terms

= 5 x^{3} - 8 y^{2} - y^{2} + \frac{1}{5} x^{3} - 6 - 10

Add similar elements:

- 8 y^{2} - y^{2} = - 9 y^{2}

= 5 x^{3} - 9 y^{2} + \frac{1}{5} x^{3} - 6 - 10

Subtract the numbers:

- 6 - 10 = - 16

= 5 x^{3} - 9 y^{2} + \frac{1}{5} x^{3} - 16

567 m^{2} - 343 = 0

- 4 x + 18 x^{5}

(x^{\frac{1}{3}})^{\frac{2}{3}}

3 + \frac{2}{3 + \frac{1}{1 + \frac{1}{4}}}

x^{- \frac{1}{5}}

What is (1/5 x^3-8y^2-6)-(y^2-5x^3+10) ?
The solution to (1/5 x^3-8y^2-6)-(y^2-5x^3+10) is 5x^3-9y^2+1/5 x^3-16