What are the solutions to the equation 2sqrt(6)^2+b^2=2sqrt(15)^2 ?

The solutions to the equation 2sqrt(6)^2+b^2=2sqrt(15)^2 are b=3sqrt(2),b=-3sqrt(2)

Find the zeros of 2sqrt(6)^2+b^2=2sqrt(15)^2

The zeros of 2sqrt(6)^2+b^2=2sqrt(15)^2 are b=3sqrt(2),b=-3sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 6^{2} + b^{2} = 2 15^{2}

b = 32, b = - 32

Decimal Notation

b = 4.24264 \dots, b = - 4.24264 \dots

Solution steps

2 (6)^{2} + b^{2} = 2 (15)^{2}

Move

2 6^{2}

to the right side

b^{2} = 18

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 18, b = - 18

18 = 32

- 18 = - 32

b = 32, b = - 32

- 6 = 23 - 2 x - 5

13 x - 52 = 91

\frac{x}{5} < - 9

(\frac{2 i ^{5} + 3 i ^{17}}{1 + i})^{2}

h^{2} + 12 h + 27

What are the solutions to the equation 2sqrt(6)^2+b^2=2sqrt(15)^2 ?
The solutions to the equation 2sqrt(6)^2+b^2=2sqrt(15)^2 are b=3sqrt(2),b=-3sqrt(2)
Find the zeros of 2sqrt(6)^2+b^2=2sqrt(15)^2
The zeros of 2sqrt(6)^2+b^2=2sqrt(15)^2 are b=3sqrt(2),b=-3sqrt(2)