What are the solutions to the equation -3x^2-4x+7=0 ?

The solutions to the equation -3x^2-4x+7=0 are x=-7/3 ,x=1

Find the zeros of -3x^2-4x+7=0

The zeros of -3x^2-4x+7=0 are x=-7/3 ,x=1

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- 3 x^{2} - 4 x + 7 = 0

x = - \frac{7}{3}, x = 1

Decimal Notation

x = - 2.33333 \dots, x = 1

Solution steps

- 3 x^{2} - 4 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 3 ) \cdot 7}{2 ( - 3 )}

(- 4)^{2} - 4 (- 3) \cdot 7 = 10

x_{1, 2} = \frac{- ( - 4 ) \pm 10}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 10}{2 ( - 3 )}, x_{2} = \frac{- ( - 4 ) - 10}{2 ( - 3 )}

x = \frac{- ( - 4 ) + 10}{2 ( - 3 )} : - \frac{7}{3}

x = \frac{- ( - 4 ) - 10}{2 ( - 3 )} : 1

The solutions to the quadratic equation are:

x = - \frac{7}{3}, x = 1

(x - 6) + (x - 4) + (x - 2) + x \leq 148

\frac{n}{4} + \frac{n}{5} = - 18

(- 2)^{2} + 4 (- 2)

64 r^{2} - 25

6^{2} + 6^{2}

What are the solutions to the equation -3x^2-4x+7=0 ?
The solutions to the equation -3x^2-4x+7=0 are x=-7/3 ,x=1
Find the zeros of -3x^2-4x+7=0
The zeros of -3x^2-4x+7=0 are x=-7/3 ,x=1