What is factor 4x^4-8x^3+28x^2 ?

The solution to factor 4x^4-8x^3+28x^2 is 4x^2(x^2-2x+7)

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factor 4x^4-8x^3+28x^2

factor

4 x^{4} - 8 x^{3} + 28 x^{2}

4 x^{2} (x^{2} - 2 x + 7)

Solution steps

4 x^{4} - 8 x^{3} + 28 x^{2}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

x^{3} = x x^{2}

= 4 x^{2} x^{2} - 8 x x^{2} + 28 x^{2}

Rewrite

8

4 \cdot 2

Rewrite

28

4 \cdot 7

= 4 x^{2} x^{2} - 4 \cdot 2 x x^{2} + 4 \cdot 7 x^{2}

Factor out common term

4 x^{2}

= 4 x^{2} (x^{2} - 2 x + 7)

\frac{9 !}{( 9 - 4 ) ! 4 !}

3 x^{2} + 18 x + 15 = 0

\frac{4 uv - 20 u w}{4 u}

(k^{\frac{1}{8}})^{- 1}

- 9 ∣ 5 u + 7 ∣ < - 9

What is factor 4x^4-8x^3+28x^2 ?
The solution to factor 4x^4-8x^3+28x^2 is 4x^2(x^2-2x+7)