What is (1+4/(c-1))/(1-4/(c-1)) ?

The solution to (1+4/(c-1))/(1-4/(c-1)) is (c+3)/(c-5)

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simplify (1+4/(c-1))/(1-4/(c-1))

simplify

\frac{1 + \frac{4}{c - 1}}{1 - \frac{4}{c - 1}}

\frac{c + 3}{c - 5}

Solution steps

\frac{1 + \frac{4}{c - 1}}{1 - \frac{4}{c - 1}}

Join

1 + \frac{4}{c - 1} : \frac{c + 3}{c - 1}

= \frac{\frac{c + 3}{c - 1}}{1 - \frac{4}{c - 1}}

Join

1 - \frac{4}{c - 1} : \frac{c - 5}{c - 1}

= \frac{\frac{c + 3}{c - 1}}{\frac{c - 5}{c - 1}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( c + 3 ) ( c - 1 )}{( c - 1 ) ( c - 5 )}

Cancel the common factor:

c - 1

= \frac{c + 3}{c - 5}

2 m - 3 (m + 1) = 4 (m + 3)

1 0^{- 4}

4^{\frac{5}{3}}

3 y^{2} - 14 y - 24

4 x^{2} + 9 x = 0

What is (1+4/(c-1))/(1-4/(c-1)) ?
The solution to (1+4/(c-1))/(1-4/(c-1)) is (c+3)/(c-5)