What are the solutions to the equation y^2-14y=-46 ?

The solutions to the equation y^2-14y=-46 are y=7+sqrt(3),y=7-sqrt(3)

Find the zeros of y^2-14y=-46

The zeros of y^2-14y=-46 are y=7+sqrt(3),y=7-sqrt(3)

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y^{2} - 14 y = - 46

y = 7 + 3, y = 7 - 3

Decimal Notation

y = 8.73205 \dots, y = 5.26794 \dots

Solution steps

y^{2} - 14 y = - 46

Move

46

to the left side

y^{2} - 14 y + 46 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 46}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 46 = 23

y_{1, 2} = \frac{- ( - 14 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 14 ) + 2 3}{2 \cdot 1}, y_{2} = \frac{- ( - 14 ) - 2 3}{2 \cdot 1}

y = \frac{- ( - 14 ) + 2 3}{2 \cdot 1} : 7 + 3

y = \frac{- ( - 14 ) - 2 3}{2 \cdot 1} : 7 - 3

The solutions to the quadratic equation are:

y = 7 + 3, y = 7 - 3

5 k^{2} - 30 k + 40

12 5^{- \frac{4}{3}}

11 x^{2} + 122 x + 11

3 x^{2} + 16 = 6 x

4 x^{2} + 6 x < 2 x + 3

What are the solutions to the equation y^2-14y=-46 ?
The solutions to the equation y^2-14y=-46 are y=7+sqrt(3),y=7-sqrt(3)
Find the zeros of y^2-14y=-46
The zeros of y^2-14y=-46 are y=7+sqrt(3),y=7-sqrt(3)