What are the solutions to the equation 5x^2+8x+2=0 ?

The solutions to the equation 5x^2+8x+2=0 are x=(-4+sqrt(6))/5 ,x=-(4+sqrt(6))/5

Find the zeros of 5x^2+8x+2=0

The zeros of 5x^2+8x+2=0 are x=(-4+sqrt(6))/5 ,x=-(4+sqrt(6))/5

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5 x^{2} + 8 x + 2 = 0

x = \frac{- 4 + 6}{5}, x = - \frac{4 + 6}{5}

Decimal Notation

x = - 0.31010 \dots, x = - 1.28989 \dots

Solution steps

5 x^{2} + 8 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 5 \cdot 2}{2 \cdot 5}

8^{2} - 4 \cdot 5 \cdot 2 = 26

x_{1, 2} = \frac{- 8 \pm 2 6}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 8 + 2 6}{2 \cdot 5}, x_{2} = \frac{- 8 - 2 6}{2 \cdot 5}

x = \frac{- 8 + 2 6}{2 \cdot 5} : \frac{- 4 + 6}{5}

x = \frac{- 8 - 2 6}{2 \cdot 5} : - \frac{4 + 6}{5}

The solutions to the quadratic equation are:

x = \frac{- 4 + 6}{5}, x = - \frac{4 + 6}{5}

36 c^{2} - 121 d^{2}

5 (x - 3) = 4 (x - 6)

6 x^{2} - 19 x + 8

\frac{3 + 2 i}{1 - 4 i}

2 (v - 1) + 4 v = 3 (v - 1) + 7

What are the solutions to the equation 5x^2+8x+2=0 ?
The solutions to the equation 5x^2+8x+2=0 are x=(-4+sqrt(6))/5 ,x=-(4+sqrt(6))/5
Find the zeros of 5x^2+8x+2=0
The zeros of 5x^2+8x+2=0 are x=(-4+sqrt(6))/5 ,x=-(4+sqrt(6))/5