What are the solutions to the equation -x^2+2x-6=0 ?

The solutions to the equation -x^2+2x-6=0 are x=1-sqrt(5)i,x=1+sqrt(5)i

Find the zeros of -x^2+2x-6=0

The zeros of -x^2+2x-6=0 are x=1-sqrt(5)i,x=1+sqrt(5)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{2} + 2 x - 6 = 0

x = 1 - 5 i, x = 1 + 5 i

Solution steps

- x^{2} + 2 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) ( - 6 )}{2 ( - 1 )}

Simplify

2^{2} - 4 (- 1) (- 6) : 25 i

x_{1, 2} = \frac{- 2 \pm 2 5 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 5 i}{2 ( - 1 )}, x_{2} = \frac{- 2 - 2 5 i}{2 ( - 1 )}

x = \frac{- 2 + 2 5 i}{2 ( - 1 )} : 1 - 5 i

x = \frac{- 2 - 2 5 i}{2 ( - 1 )} : 1 + 5 i

The solutions to the quadratic equation are:

x = 1 - 5 i, x = 1 + 5 i

x^{3} - 4 x^{2} - 5 x

2 x^{2} - 9 x + 4 > 0

- \frac{50}{5 ^{3}} + \frac{5}{5 ^{2}}

3 (4 k - 2) = 16 k - 32

\frac{1}{9 ^{3}}

What are the solutions to the equation -x^2+2x-6=0 ?
The solutions to the equation -x^2+2x-6=0 are x=1-sqrt(5)i,x=1+sqrt(5)i
Find the zeros of -x^2+2x-6=0
The zeros of -x^2+2x-6=0 are x=1-sqrt(5)i,x=1+sqrt(5)i