What are the solutions to the equation 3r^2+3r-3=0 ?

The solutions to the equation 3r^2+3r-3=0 are r=(-1+sqrt(5))/2 ,r=-(1+sqrt(5))/2

Find the zeros of 3r^2+3r-3=0

The zeros of 3r^2+3r-3=0 are r=(-1+sqrt(5))/2 ,r=-(1+sqrt(5))/2

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3 r^{2} + 3 r - 3 = 0

r = \frac{- 1 + 5}{2}, r = - \frac{1 + 5}{2}

Decimal Notation

r = 0.61803 \dots, r = - 1.61803 \dots

Solution steps

3 r^{2} + 3 r - 3 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

3^{2} - 4 \cdot 3 (- 3) = 35

r_{1, 2} = \frac{- 3 \pm 3 5}{2 \cdot 3}

Separate the solutions

r_{1} = \frac{- 3 + 3 5}{2 \cdot 3}, r_{2} = \frac{- 3 - 3 5}{2 \cdot 3}

r = \frac{- 3 + 3 5}{2 \cdot 3} : \frac{- 1 + 5}{2}

r = \frac{- 3 - 3 5}{2 \cdot 3} : - \frac{1 + 5}{2}

The solutions to the quadratic equation are:

r = \frac{- 1 + 5}{2}, r = - \frac{1 + 5}{2}

9 x^{3} + 27 x^{2} - x - 3

6 s - \frac{4 s - 1}{2} = 3

(m - 4) (3 m - 10) = 3 (m - 2) + 18

63 y^{2} - 28

2 p - 4 < - 3 p - 7

What are the solutions to the equation 3r^2+3r-3=0 ?
The solutions to the equation 3r^2+3r-3=0 are r=(-1+sqrt(5))/2 ,r=-(1+sqrt(5))/2
Find the zeros of 3r^2+3r-3=0
The zeros of 3r^2+3r-3=0 are r=(-1+sqrt(5))/2 ,r=-(1+sqrt(5))/2