What are the solutions to the equation x^2+12^2=13^2 ?

The solutions to the equation x^2+12^2=13^2 are x=5,x=-5

Find the zeros of x^2+12^2=13^2

The zeros of x^2+12^2=13^2 are x=5,x=-5

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x^{2} + 1 2^{2} = 1 3^{2}

x = 5, x = - 5

Solution steps

x^{2} + 1 2^{2} = 1 3^{2}

Move

1 2^{2}

to the right side

x^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 25, x = - 25

25 = 5

- 25 = - 5

x = 5, x = - 5

3 + y = \frac{( 3 y + 9 )}{3}

∣ x - 4 ∣ \leq 14

\frac{4 ( x + 2 )}{6} = 2 x - 4

8 x^{2} + 24 x = 0

(\frac{2}{5})^{- 1}

What are the solutions to the equation x^2+12^2=13^2 ?
The solutions to the equation x^2+12^2=13^2 are x=5,x=-5
Find the zeros of x^2+12^2=13^2
The zeros of x^2+12^2=13^2 are x=5,x=-5