What are the solutions to the equation 2x^2+6x+6=0 ?

The solutions to the equation 2x^2+6x+6=0 are x=-3/2+i(sqrt(3))/2 ,x=-3/2-i(sqrt(3))/2

Find the zeros of 2x^2+6x+6=0

The zeros of 2x^2+6x+6=0 are x=-3/2+i(sqrt(3))/2 ,x=-3/2-i(sqrt(3))/2

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2 x^{2} + 6 x + 6 = 0

x = - \frac{3}{2} + i \frac{3}{2}, x = - \frac{3}{2} - i \frac{3}{2}

Solution steps

2 x^{2} + 6 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

Simplify

6^{2} - 4 \cdot 2 \cdot 6 : 23 i

x_{1, 2} = \frac{- 6 \pm 2 3 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 6 + 2 3 i}{2 \cdot 2}, x_{2} = \frac{- 6 - 2 3 i}{2 \cdot 2}

x = \frac{- 6 + 2 3 i}{2 \cdot 2} : - \frac{3}{2} + i \frac{3}{2}

x = \frac{- 6 - 2 3 i}{2 \cdot 2} : - \frac{3}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2} + i \frac{3}{2}, x = - \frac{3}{2} - i \frac{3}{2}

3 - 2 x < 1

2 n^{3} - 4 n^{2} - n + 2

\frac{x ^{2}}{3} - x = - \frac{1}{2}

12 x^{2} + 12 x - 826 = 0

2 u^{2} - 5 u - 7

What are the solutions to the equation 2x^2+6x+6=0 ?
The solutions to the equation 2x^2+6x+6=0 are x=-3/2+i(sqrt(3))/2 ,x=-3/2-i(sqrt(3))/2
Find the zeros of 2x^2+6x+6=0
The zeros of 2x^2+6x+6=0 are x=-3/2+i(sqrt(3))/2 ,x=-3/2-i(sqrt(3))/2