What are the solutions to the equation x^2-8=-2x ?

The solutions to the equation x^2-8=-2x are x=2,x=-4

Find the zeros of x^2-8=-2x

The zeros of x^2-8=-2x are x=2,x=-4

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x^{2} - 8 = - 2 x

x = 2, x = - 4

Solution steps

x^{2} - 8 = - 2 x

Move

2 x

to the left side

x^{2} - 8 + 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 8) = 6

x_{1, 2} = \frac{- 2 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 6}{2 \cdot 1}, x_{2} = \frac{- 2 - 6}{2 \cdot 1}

x = \frac{- 2 + 6}{2 \cdot 1} : 2

x = \frac{- 2 - 6}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 2, x = - 4

\frac{e ^{2 x}}{4} + \frac{1}{2} + \frac{e ^{- 2 x}}{4}

(x + 4)^{2} - (2 x - 1)^{2} = 8 x

6 x^{2} - 3 x = 0

6 + \frac{4}{x} \geq 0

\frac{- \frac{3}{5}}{\frac{4}{5}}

What are the solutions to the equation x^2-8=-2x ?
The solutions to the equation x^2-8=-2x are x=2,x=-4
Find the zeros of x^2-8=-2x
The zeros of x^2-8=-2x are x=2,x=-4