What is 12x-39<= 9\land-4x+3<-6 ?

The solution to 12x-39<= 9\land-4x+3<-6 is 9/4 <x<= 4

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12x-39<= 9\land-4x+3<-6

12 x - 39 \leq 9 and - 4 x + 3 < - 6

\frac{9}{4} < x \leq 4

Interval Notation

(\frac{9}{4}, 4]

Decimal Notation

2.25 < x \leq 4

Solution steps

12 x - 39 \leq 9 and - 4 x + 3 < - 6

12 x - 39 \leq 9 : x \leq 4

- 4 x + 3 < - 6 : x > \frac{9}{4}

Combine the intervals

x \leq 4 and x > \frac{9}{4}

Merge Overlapping Intervals

\frac{9}{4} < x \leq 4

(x - 1) \cdot (x - 2) \cdot (x + 2) \cdot (x + 3) - 60

\frac{x}{3} = - 48

12 k t - 48 k + 9 t - 36

- 8 k^{2} - 12 k + 108 > 0

\frac{5 x + 9}{3} + \frac{x}{2} = 10

What is 12x-39<= 9\land-4x+3<-6 ?
The solution to 12x-39<= 9\land-4x+3<-6 is 9/4 <x<= 4