What are the solutions to the equation r^2+34=0 ?

The solutions to the equation r^2+34=0 are r=sqrt(34)i,r=-sqrt(34)i

Find the zeros of r^2+34=0

The zeros of r^2+34=0 are r=sqrt(34)i,r=-sqrt(34)i

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r^{2} + 34 = 0

r = 34 i, r = - 34 i

Solution steps

r^{2} + 34 = 0

Move

34

to the right side

r^{2} = - 34

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = - 34, r = - - 34

- 34 = 34 i

- - 34 = - 34 i

r = 34 i, r = - 34 i

10 y^{3} + 17 y^{2} + 3 y

x^{2} = x - 4

\frac{1}{3} n + \frac{29}{6} = 2 (\frac{4}{3} n + \frac{2}{3})

- 5 - 3

- \frac{3}{8} \cdot 4

What are the solutions to the equation r^2+34=0 ?
The solutions to the equation r^2+34=0 are r=sqrt(34)i,r=-sqrt(34)i
Find the zeros of r^2+34=0
The zeros of r^2+34=0 are r=sqrt(34)i,r=-sqrt(34)i