What are the solutions to the equation x^2+3x-10=18 ?

The solutions to the equation x^2+3x-10=18 are x=4,x=-7

Find the zeros of x^2+3x-10=18

The zeros of x^2+3x-10=18 are x=4,x=-7

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x^{2} + 3 x - 10 = 18

x = 4, x = - 7

Solution steps

x^{2} + 3 x - 10 = 18

Move

18

to the left side

x^{2} + 3 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 28) = 11

x_{1, 2} = \frac{- 3 \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 11}{2 \cdot 1}, x_{2} = \frac{- 3 - 11}{2 \cdot 1}

x = \frac{- 3 + 11}{2 \cdot 1} : 4

x = \frac{- 3 - 11}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 4, x = - 7

(\frac{7}{9}) v + 16 = 27

6 (x + 6)^{2} (2 x - 5) - (x + 6) (2 x + 5)^{3}

\frac{1}{6} \cdot \frac{1}{6}

x - 21 = 6

\frac{15}{3} - \frac{4}{9} - \frac{1}{6} + \frac{11}{18} - \frac{1}{36} + 2

What are the solutions to the equation x^2+3x-10=18 ?
The solutions to the equation x^2+3x-10=18 are x=4,x=-7
Find the zeros of x^2+3x-10=18
The zeros of x^2+3x-10=18 are x=4,x=-7