What are the solutions to the equation 11x^2-5x+2=0 ?

The solutions to the equation 11x^2-5x+2=0 are x= 5/22+i(3sqrt(7))/(22),x= 5/22-i(3sqrt(7))/(22)

Find the zeros of 11x^2-5x+2=0

The zeros of 11x^2-5x+2=0 are x= 5/22+i(3sqrt(7))/(22),x= 5/22-i(3sqrt(7))/(22)

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11 x^{2} - 5 x + 2 = 0

x = \frac{5}{22} + i \frac{3 7}{22}, x = \frac{5}{22} - i \frac{3 7}{22}

Solution steps

11 x^{2} - 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 11 \cdot 2}{2 \cdot 11}

Simplify

(- 5)^{2} - 4 \cdot 11 \cdot 2 : 37 i

x_{1, 2} = \frac{- ( - 5 ) \pm 3 7 i}{2 \cdot 11}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3 7 i}{2 \cdot 11}, x_{2} = \frac{- ( - 5 ) - 3 7 i}{2 \cdot 11}

x = \frac{- ( - 5 ) + 3 7 i}{2 \cdot 11} : \frac{5}{22} + i \frac{3 7}{22}

x = \frac{- ( - 5 ) - 3 7 i}{2 \cdot 11} : \frac{5}{22} - i \frac{3 7}{22}

The solutions to the quadratic equation are:

x = \frac{5}{22} + i \frac{3 7}{22}, x = \frac{5}{22} - i \frac{3 7}{22}

\frac{x - 1}{x + 1} \geq 1

15 u - 12 v + 9

3 x^{2} - 18 x + 27

x^{2} - 3 x + 2 = 6 \cdot 0.7

x - 3 x^{2} < ∣ 1 - 3 x ∣

What are the solutions to the equation 11x^2-5x+2=0 ?
The solutions to the equation 11x^2-5x+2=0 are x= 5/22+i(3sqrt(7))/(22),x= 5/22-i(3sqrt(7))/(22)
Find the zeros of 11x^2-5x+2=0
The zeros of 11x^2-5x+2=0 are x= 5/22+i(3sqrt(7))/(22),x= 5/22-i(3sqrt(7))/(22)