What are the solutions to the equation 3a^2-4=6a ?

The solutions to the equation 3a^2-4=6a are a=(3+sqrt(21))/3 ,a=(3-sqrt(21))/3

Find the zeros of 3a^2-4=6a

The zeros of 3a^2-4=6a are a=(3+sqrt(21))/3 ,a=(3-sqrt(21))/3

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3 a^{2} - 4 = 6 a

a = \frac{3 + 21}{3}, a = \frac{3 - 21}{3}

Decimal Notation

a = 2.52752 \dots, a = - 0.52752 \dots

Solution steps

3 a^{2} - 4 = 6 a

Move

6 a

to the left side

3 a^{2} - 4 - 6 a = 0

Write in the standard form

a x^{2} + b x + c = 0

3 a^{2} - 6 a - 4 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 (- 4) = 221

a_{1, 2} = \frac{- ( - 6 ) \pm 2 21}{2 \cdot 3}

Separate the solutions

a_{1} = \frac{- ( - 6 ) + 2 21}{2 \cdot 3}, a_{2} = \frac{- ( - 6 ) - 2 21}{2 \cdot 3}

a = \frac{- ( - 6 ) + 2 21}{2 \cdot 3} : \frac{3 + 21}{3}

a = \frac{- ( - 6 ) - 2 21}{2 \cdot 3} : \frac{3 - 21}{3}

The solutions to the quadratic equation are:

a = \frac{3 + 21}{3}, a = \frac{3 - 21}{3}

6 x - 47 = - 5 (x - 6)

6 x^{2} - 13 x + 5 = 0

130 + 20 x > 350

0 = - \frac{5}{4} (x - \frac{6}{5})

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What are the solutions to the equation 3a^2-4=6a ?
The solutions to the equation 3a^2-4=6a are a=(3+sqrt(21))/3 ,a=(3-sqrt(21))/3
Find the zeros of 3a^2-4=6a
The zeros of 3a^2-4=6a are a=(3+sqrt(21))/3 ,a=(3-sqrt(21))/3