What is sqrt(x+4)>= 2sqrt(x) ?

The solution to sqrt(x+4)>= 2sqrt(x) is 0<= x<= 4/3

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sqrt(x+4)>= 2sqrt(x)

x + 4 \geq 2 x

0 \leq x \leq \frac{4}{3}

Interval Notation

[0, \frac{4}{3}]

Decimal Notation

0 \leq x \leq 1.33333 \dots

Solution steps

x + 4 \geq 2 x

f (x) \geq g (x)

then

g (x) < 0 or g (x) \geq 0

For

2 x < 0 :

No Solution

For

2 x \geq 0 : x \leq \frac{4}{3}

Find singularity points

Find non-negative values for radicals:

x \geq 0

Combine the intervals

(x \leq \frac{4}{3} or No Solution) and x \geq 0

Merge Overlapping Intervals

0 \leq x \leq \frac{4}{3}

(45 t - 16 t^{2}) - 26

7 x - 2 x = 55

\frac{1}{32}

72 = 2 x^{2}

- 3 - (- 6)

What is sqrt(x+4)>= 2sqrt(x) ?
The solution to sqrt(x+4)>= 2sqrt(x) is 0<= x<= 4/3