What are the solutions to the equation -3x^2+2x=0 ?

The solutions to the equation -3x^2+2x=0 are x=0,x= 2/3

Find the zeros of -3x^2+2x=0

The zeros of -3x^2+2x=0 are x=0,x= 2/3

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- 3 x^{2} + 2 x = 0

x = 0, x = \frac{2}{3}

Decimal Notation

x = 0, x = 0.66666 \dots

Solution steps

- 3 x^{2} + 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 3 ) \cdot 0}{2 ( - 3 )}

2^{2} - 4 (- 3) \cdot 0 = 2

x_{1, 2} = \frac{- 2 \pm 2}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 2 + 2}{2 ( - 3 )}, x_{2} = \frac{- 2 - 2}{2 ( - 3 )}

x = \frac{- 2 + 2}{2 ( - 3 )} : 0

x = \frac{- 2 - 2}{2 ( - 3 )} : \frac{2}{3}

The solutions to the quadratic equation are:

x = 0, x = \frac{2}{3}

2.5 + 0.15 p = 0.4 p

3 x - 9 = 0

- 4 + 3

m^{2} - 7 m - 8

(- 2 - 10) (- 3)

What are the solutions to the equation -3x^2+2x=0 ?
The solutions to the equation -3x^2+2x=0 are x=0,x= 2/3
Find the zeros of -3x^2+2x=0
The zeros of -3x^2+2x=0 are x=0,x= 2/3