What are the solutions to the equation 49x^2+112x+64=0 ?

The solutions to the equation 49x^2+112x+64=0 are x=-8/7

Find the zeros of 49x^2+112x+64=0

The zeros of 49x^2+112x+64=0 are x=-8/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

49 x^{2} + 112 x + 64 = 0

x = - \frac{8}{7}

Decimal Notation

x = - 1.14285 \dots

Solution steps

49 x^{2} + 112 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 112 \pm 11 2 ^{2} - 4 \cdot 49 \cdot 64}{2 \cdot 49}

11 2^{2} - 4 \cdot 49 \cdot 64 = 0

x_{1, 2} = \frac{- 112 \pm 0}{2 \cdot 49}

x = \frac{- 112}{2 \cdot 49}

\frac{- 112}{2 \cdot 49} = - \frac{8}{7}

x = - \frac{8}{7}

The solution to the quadratic equation is:

x = - \frac{8}{7}

\frac{2}{3} - \frac{3}{3}

(\frac{7}{5})^{2}

6 4^{\frac{5}{3}}

- 3 x + 8 < 15

- 7 (x + 3) + 6 (2 x + 9) = 6 (x + 3)

What are the solutions to the equation 49x^2+112x+64=0 ?
The solutions to the equation 49x^2+112x+64=0 are x=-8/7
Find the zeros of 49x^2+112x+64=0
The zeros of 49x^2+112x+64=0 are x=-8/7