What are the solutions to the equation 15x^2-38x-11=0 ?

The solutions to the equation 15x^2-38x-11=0 are x=(19+sqrt(526))/(15),x=(19-sqrt(526))/(15)

Find the zeros of 15x^2-38x-11=0

The zeros of 15x^2-38x-11=0 are x=(19+sqrt(526))/(15),x=(19-sqrt(526))/(15)

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15 x^{2} - 38 x - 11 = 0

x = \frac{19 + 526}{15}, x = \frac{19 - 526}{15}

Decimal Notation

x = 2.79564 \dots, x = - 0.26231 \dots

Solution steps

15 x^{2} - 38 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 38 ) \pm ( - 38 ) ^{2} - 4 \cdot 15 ( - 11 )}{2 \cdot 15}

(- 38)^{2} - 4 \cdot 15 (- 11) = 2526

x_{1, 2} = \frac{- ( - 38 ) \pm 2 526}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 38 ) + 2 526}{2 \cdot 15}, x_{2} = \frac{- ( - 38 ) - 2 526}{2 \cdot 15}

x = \frac{- ( - 38 ) + 2 526}{2 \cdot 15} : \frac{19 + 526}{15}

x = \frac{- ( - 38 ) - 2 526}{2 \cdot 15} : \frac{19 - 526}{15}

The solutions to the quadratic equation are:

x = \frac{19 + 526}{15}, x = \frac{19 - 526}{15}

9!

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What are the solutions to the equation 15x^2-38x-11=0 ?
The solutions to the equation 15x^2-38x-11=0 are x=(19+sqrt(526))/(15),x=(19-sqrt(526))/(15)
Find the zeros of 15x^2-38x-11=0
The zeros of 15x^2-38x-11=0 are x=(19+sqrt(526))/(15),x=(19-sqrt(526))/(15)