What is (20cd)/(28bcd) ?

The solution to (20cd)/(28bcd) is 5/(7b)

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simplify (20cd)/(28bcd)

simplify

\frac{20 c d}{28 b c d}

\frac{5}{7 b}

Solution steps

\frac{20 c d}{28 b c d}

Cancel the common factor:

c

= \frac{20 d}{28 b d}

Cancel the common factor:

d

= \frac{20}{28 b}

Factor the number:

20 = 4 \cdot 5

= \frac{4 \cdot 5}{28 b}

Factor the number:

28 = 4 \cdot 7

= \frac{4 \cdot 5}{4 \cdot 7 b}

Cancel the common factor:

4

= \frac{5}{7 b}

\frac{5}{2} - \frac{1}{2}

\frac{10 18}{12}

∣ x - 7 ∣ = 9

\frac{d}{10} = 4

2 x^{3} - 5 x + 3