What is ((x^2-10x+24))/(x^2-1)<= 0 ?

The solution to ((x^2-10x+24))/(x^2-1)<= 0 is -1<x<1\lor 4<= x<= 6

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((x^2-10x+24))/(x^2-1)<= 0

\frac{( x ^{2} - 10 x + 24 )}{x ^{2} - 1} \leq 0

- 1 < x < 1 or 4 \leq x \leq 6

Interval Notation

(- 1, 1) \cup [4, 6]

Solution steps

\frac{x ^{2} - 10 x + 24}{x ^{2} - 1} \leq 0

Factor

\frac{x ^{2} - 10 x + 24}{x ^{2} - 1} : \frac{( x - 4 ) ( x - 6 )}{( x + 1 ) ( x - 1 )}

\frac{( x - 4 ) ( x - 6 )}{( x + 1 ) ( x - 1 )} \leq 0

Identify the intervals

- 1 < x < 1 or 4 \leq x \leq 6

\frac{8 x ^{6} y ^{- 10} z ^{35}}{20 x ^{- 2} y ^{4} z ^{5}}

- 1.8 x \leq 36

2 (2 x - 1) > \frac{( 5 x - 4 )}{2}

(1.25)^{\frac{2}{12}} - 1

y^{2} - 10 y + 21

What is ((x^2-10x+24))/(x^2-1)<= 0 ?
The solution to ((x^2-10x+24))/(x^2-1)<= 0 is -1<x<1\lor 4<= x<= 6