What are the solutions to the equation (2x-4)^2=98 ?

The solutions to the equation (2x-4)^2=98 are x=(7sqrt(2)+4)/2 ,x=(-7sqrt(2)+4)/2

Find the zeros of (2x-4)^2=98

The zeros of (2x-4)^2=98 are x=(7sqrt(2)+4)/2 ,x=(-7sqrt(2)+4)/2

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(2 x - 4)^{2} = 98

x = \frac{7 2 + 4}{2}, x = \frac{- 7 2 + 4}{2}

Decimal Notation

x = 6.94974 \dots, x = - 2.94974 \dots

Solution steps

(2 x - 4)^{2} = 98

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 4 = 98 : x = \frac{7 2 + 4}{2}

Solve

2 x - 4 = - 98 : x = \frac{- 7 2 + 4}{2}

The solutions to the quadratic equation are:

x = \frac{7 2 + 4}{2}, x = \frac{- 7 2 + 4}{2}

6 x^{2} - 17 x + 5

(49 - 1)^{2}

\frac{3 x ^{- 3} y ^{3}}{9 x ^{2} ( y ^{- 3} ) ^{2}}

x^{2} - 1 \leq 3

What are the solutions to the equation (2x-4)^2=98 ?
The solutions to the equation (2x-4)^2=98 are x=(7sqrt(2)+4)/2 ,x=(-7sqrt(2)+4)/2
Find the zeros of (2x-4)^2=98
The zeros of (2x-4)^2=98 are x=(7sqrt(2)+4)/2 ,x=(-7sqrt(2)+4)/2