What are the solutions to the equation 16x^2+8x=-1 ?

The solutions to the equation 16x^2+8x=-1 are x=-1/4

Find the zeros of 16x^2+8x=-1

The zeros of 16x^2+8x=-1 are x=-1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16 x^{2} + 8 x = - 1

x = - \frac{1}{4}

Decimal Notation

x = - 0.25

Solution steps

16 x^{2} + 8 x = - 1

Move

1

to the left side

16 x^{2} + 8 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 16 \cdot 1}{2 \cdot 16}

8^{2} - 4 \cdot 16 \cdot 1 = 0

x_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 16}

x = \frac{- 8}{2 \cdot 16}

\frac{- 8}{2 \cdot 16} = - \frac{1}{4}

x = - \frac{1}{4}

The solution to the quadratic equation is:

x = - \frac{1}{4}

10 = 32 t - 5 t^{2}

(x^{2}) = 35

n - 6 \leq - 14

3 x^{3} - 3 x

x^{2} + x + 9.25 = 0

What are the solutions to the equation 16x^2+8x=-1 ?
The solutions to the equation 16x^2+8x=-1 are x=-1/4
Find the zeros of 16x^2+8x=-1
The zeros of 16x^2+8x=-1 are x=-1/4