What are the solutions to the equation x^2+18x+10=-9 ?

The solutions to the equation x^2+18x+10=-9 are x=-9+sqrt(62),x=-9-sqrt(62)

Find the zeros of x^2+18x+10=-9

The zeros of x^2+18x+10=-9 are x=-9+sqrt(62),x=-9-sqrt(62)

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x^{2} + 18 x + 10 = - 9

x = - 9 + 62, x = - 9 - 62

Decimal Notation

x = - 1.12599 \dots, x = - 16.87400 \dots

Solution steps

x^{2} + 18 x + 10 = - 9

Move

9

to the left side

x^{2} + 18 x + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 19}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 19 = 262

x_{1, 2} = \frac{- 18 \pm 2 62}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 2 62}{2 \cdot 1}, x_{2} = \frac{- 18 - 2 62}{2 \cdot 1}

x = \frac{- 18 + 2 62}{2 \cdot 1} : - 9 + 62

x = \frac{- 18 - 2 62}{2 \cdot 1} : - 9 - 62

The solutions to the quadratic equation are:

x = - 9 + 62, x = - 9 - 62

3 x + 7 - 5 (2 x - 3) \geq \frac{( x - 1 )}{2} - 1

x^{2} - 11 x + 24 \leq 0

- x^{2} + 3 x - 1 = 0

0.2 b + 6 = 0.5 b + 12

\frac{1}{1 + ( 0.2 ) ^{2}}

What are the solutions to the equation x^2+18x+10=-9 ?
The solutions to the equation x^2+18x+10=-9 are x=-9+sqrt(62),x=-9-sqrt(62)
Find the zeros of x^2+18x+10=-9
The zeros of x^2+18x+10=-9 are x=-9+sqrt(62),x=-9-sqrt(62)