What are the solutions to the equation (x+7)^2=1 ?

The solutions to the equation (x+7)^2=1 are x=-6,x=-8

Find the zeros of (x+7)^2=1

The zeros of (x+7)^2=1 are x=-6,x=-8

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(x + 7)^{2} = 1

x = - 6, x = - 8

Solution steps

(x + 7)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = 1 : x = - 6

Solve

x + 7 = - 1 : x = - 8

The solutions to the quadratic equation are:

x = - 6, x = - 8

123 - 11 t - 16 t^{2} = 0

\frac{1}{4} + \frac{2}{3}

(\frac{11}{2})^{2}

6 x^{2} - 2 x - 8 = 0

\frac{- 13.4}{- 9.35}

What are the solutions to the equation (x+7)^2=1 ?
The solutions to the equation (x+7)^2=1 are x=-6,x=-8
Find the zeros of (x+7)^2=1
The zeros of (x+7)^2=1 are x=-6,x=-8