What are the solutions to the equation 3x^2-4x+5=0 ?

The solutions to the equation 3x^2-4x+5=0 are x= 2/3+i(sqrt(11))/3 ,x= 2/3-i(sqrt(11))/3

Find the zeros of 3x^2-4x+5=0

The zeros of 3x^2-4x+5=0 are x= 2/3+i(sqrt(11))/3 ,x= 2/3-i(sqrt(11))/3

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3 x^{2} - 4 x + 5 = 0

x = \frac{2}{3} + i \frac{11}{3}, x = \frac{2}{3} - i \frac{11}{3}

Solution steps

3 x^{2} - 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

Simplify

(- 4)^{2} - 4 \cdot 3 \cdot 5 : 211 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 11 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 11 i}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 2 11 i}{2 \cdot 3}

x = \frac{- ( - 4 ) + 2 11 i}{2 \cdot 3} : \frac{2}{3} + i \frac{11}{3}

x = \frac{- ( - 4 ) - 2 11 i}{2 \cdot 3} : \frac{2}{3} - i \frac{11}{3}

The solutions to the quadratic equation are:

x = \frac{2}{3} + i \frac{11}{3}, x = \frac{2}{3} - i \frac{11}{3}

s^{2} + 4 s + 5 = 0

4 y^{2} + 12 y + 9

2 5 x - 6 - 1 < 5

\frac{3}{4} = 1 - \frac{x}{2}

5 x^{2} - 12 = 28 x

What are the solutions to the equation 3x^2-4x+5=0 ?
The solutions to the equation 3x^2-4x+5=0 are x= 2/3+i(sqrt(11))/3 ,x= 2/3-i(sqrt(11))/3
Find the zeros of 3x^2-4x+5=0
The zeros of 3x^2-4x+5=0 are x= 2/3+i(sqrt(11))/3 ,x= 2/3-i(sqrt(11))/3