What are the solutions to the equation -6x^2-96x+13=13 ?

The solutions to the equation -6x^2-96x+13=13 are x=-16,x=0

Find the zeros of -6x^2-96x+13=13

The zeros of -6x^2-96x+13=13 are x=-16,x=0

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- 6 x^{2} - 96 x + 13 = 13

x = - 16, x = 0

Solution steps

- 6 x^{2} - 96 x + 13 = 13

Move

13

to the left side

- 6 x^{2} - 96 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 96 ) \pm ( - 96 ) ^{2} - 4 ( - 6 ) \cdot 0}{2 ( - 6 )}

(- 96)^{2} - 4 (- 6) \cdot 0 = 96

x_{1, 2} = \frac{- ( - 96 ) \pm 96}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- ( - 96 ) + 96}{2 ( - 6 )}, x_{2} = \frac{- ( - 96 ) - 96}{2 ( - 6 )}

x = \frac{- ( - 96 ) + 96}{2 ( - 6 )} : - 16

x = \frac{- ( - 96 ) - 96}{2 ( - 6 )} : 0

The solutions to the quadratic equation are:

x = - 16, x = 0

(2 + 5 i)^{2}

- 8 \leq x \leq - 3

∣ 2 x + 2 ∣ = 14

1 - u (t)

f + \frac{1}{4} = - \frac{7}{2}

What are the solutions to the equation -6x^2-96x+13=13 ?
The solutions to the equation -6x^2-96x+13=13 are x=-16,x=0
Find the zeros of -6x^2-96x+13=13
The zeros of -6x^2-96x+13=13 are x=-16,x=0