What are the solutions to the equation x(2x-3)=27 ?

The solutions to the equation x(2x-3)=27 are x= 9/2 ,x=-3

Find the zeros of x(2x-3)=27

The zeros of x(2x-3)=27 are x= 9/2 ,x=-3

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x (2 x - 3) = 27

x = \frac{9}{2}, x = - 3

Decimal Notation

x = 4.5, x = - 3

Solution steps

x (2 x - 3) = 27

Expand

x (2 x - 3) : 2 x^{2} - 3 x

2 x^{2} - 3 x = 27

Move

27

to the left side

2 x^{2} - 3 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 27 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 27) = 15

x_{1, 2} = \frac{- ( - 3 ) \pm 15}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 15}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 15}{2 \cdot 2}

x = \frac{- ( - 3 ) + 15}{2 \cdot 2} : \frac{9}{2}

x = \frac{- ( - 3 ) - 15}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = \frac{9}{2}, x = - 3

y^{2} + 11 y - 12

n^{2} + 14 n + 49

3 x^{2} + x + 13 = 0

\frac{2}{3} + \frac{4}{5}

7 x y + 14 x - 35 y - 70

What are the solutions to the equation x(2x-3)=27 ?
The solutions to the equation x(2x-3)=27 are x= 9/2 ,x=-3
Find the zeros of x(2x-3)=27
The zeros of x(2x-3)=27 are x= 9/2 ,x=-3