What are the solutions to the equation 2t^2-5t-3=0 ?

The solutions to the equation 2t^2-5t-3=0 are t=3,t=-1/2

Find the zeros of 2t^2-5t-3=0

The zeros of 2t^2-5t-3=0 are t=3,t=-1/2

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2 t^{2} - 5 t - 3 = 0

t = 3, t = - \frac{1}{2}

Decimal Notation

t = 3, t = - 0.5

Solution steps

2 t^{2} - 5 t - 3 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 3) = 7

t_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 2}

Separate the solutions

t_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 2}, t_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 2}

t = \frac{- ( - 5 ) + 7}{2 \cdot 2} : 3

t = \frac{- ( - 5 ) - 7}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

t = 3, t = - \frac{1}{2}

4 2 x - 3 < 12

\frac{1}{9} \cdot \frac{5}{4}

\frac{- 6 \cdot 1 0 ^{- 9}}{8.85 \cdot 1 0 ^{- 12}}

- 34

ln (ln (1))

What are the solutions to the equation 2t^2-5t-3=0 ?
The solutions to the equation 2t^2-5t-3=0 are t=3,t=-1/2
Find the zeros of 2t^2-5t-3=0
The zeros of 2t^2-5t-3=0 are t=3,t=-1/2