What are the solutions to the equation m^2+10m=-21 ?

The solutions to the equation m^2+10m=-21 are m=-3,m=-7

Find the zeros of m^2+10m=-21

The zeros of m^2+10m=-21 are m=-3,m=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

m^{2} + 10 m = - 21

m = - 3, m = - 7

Solution steps

m^{2} + 10 m = - 21

Move

21

to the left side

m^{2} + 10 m + 21 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 21 = 4

m_{1, 2} = \frac{- 10 \pm 4}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 10 + 4}{2 \cdot 1}, m_{2} = \frac{- 10 - 4}{2 \cdot 1}

m = \frac{- 10 + 4}{2 \cdot 1} : - 3

m = \frac{- 10 - 4}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

m = - 3, m = - 7

- 4 + 9 x - 2 x^{2} = 0

0 + \frac{π}{8}

- 2 x^{2} - 3 x + 4 \leq 2

\frac{6}{7} \cdot \frac{6}{7}

\frac{7}{10} (x + 8) = 18

What are the solutions to the equation m^2+10m=-21 ?
The solutions to the equation m^2+10m=-21 are m=-3,m=-7
Find the zeros of m^2+10m=-21
The zeros of m^2+10m=-21 are m=-3,m=-7