What is factor 2s^2+3s+1 ?

The solution to factor 2s^2+3s+1 is (2s+1)(s+1)

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factor 2s^2+3s+1

factor

2 s^{2} + 3 s + 1

(2 s + 1) (s + 1)

Solution steps

2 s^{2} + 3 s + 1

Break the expression into groups

= (2 s^{2} + s) + (2 s + 1)

Factor out

s

from

2 s^{2} + s : s (2 s + 1)

= s (2 s + 1) + (2 s + 1)

Factor out common term

(2 s + 1) : (2 s + 1) (s + 1)

= (2 s + 1) (s + 1)

y + 6 > 5

\frac{7 ^{14}}{7 ^{2}}

\frac{1}{8} - \frac{1}{5} + \frac{1}{12}

9 x^{2} + 6 x + 1 > 0

\frac{e ^{2 x + 5}}{e ^{1 + 2 x}}