What are the solutions to the equation 0=5(2x-5)(x+6) ?

The solutions to the equation 0=5(2x-5)(x+6) are x= 5/2 ,x=-6

Find the zeros of 0=5(2x-5)(x+6)

The zeros of 0=5(2x-5)(x+6) are x= 5/2 ,x=-6

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0 = 5 (2 x - 5) (x + 6)

x = \frac{5}{2}, x = - 6

Solution steps

0 = 5 (2 x - 5) (x + 6)

Switch sides

5 (2 x - 5) (x + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 5 = 0 or x + 6 = 0

Solve

2 x - 5 = 0 : x = \frac{5}{2}

Solve

x + 6 = 0 : x = - 6

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - 6

\frac{3 x - 6}{5} + 1 = 2 x

x^{3} + 13 x^{2} + 26 x - 40

10 0^{\frac{1}{2}} \cdot 2 5^{- 2}

- 3 (w + 2) = 2 (w + 6) + 7

6000 - 25 p = 4000

What are the solutions to the equation 0=5(2x-5)(x+6) ?
The solutions to the equation 0=5(2x-5)(x+6) are x= 5/2 ,x=-6
Find the zeros of 0=5(2x-5)(x+6)
The zeros of 0=5(2x-5)(x+6) are x= 5/2 ,x=-6