What are the solutions to the equation 5x^2-20x+36=0 ?

The solutions to the equation 5x^2-20x+36=0 are x=2+i(4sqrt(5))/5 ,x=2-i(4sqrt(5))/5

Find the zeros of 5x^2-20x+36=0

The zeros of 5x^2-20x+36=0 are x=2+i(4sqrt(5))/5 ,x=2-i(4sqrt(5))/5

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5 x^{2} - 20 x + 36 = 0

x = 2 + i \frac{4 5}{5}, x = 2 - i \frac{4 5}{5}

Solution steps

5 x^{2} - 20 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 5 \cdot 36}{2 \cdot 5}

Simplify

(- 20)^{2} - 4 \cdot 5 \cdot 36 : 85 i

x_{1, 2} = \frac{- ( - 20 ) \pm 8 5 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 8 5 i}{2 \cdot 5}, x_{2} = \frac{- ( - 20 ) - 8 5 i}{2 \cdot 5}

x = \frac{- ( - 20 ) + 8 5 i}{2 \cdot 5} : 2 + i \frac{4 5}{5}

x = \frac{- ( - 20 ) - 8 5 i}{2 \cdot 5} : 2 - i \frac{4 5}{5}

The solutions to the quadratic equation are:

x = 2 + i \frac{4 5}{5}, x = 2 - i \frac{4 5}{5}

\frac{2}{3} \cdot 6 + 12 = 8 + c \cdot 6

2 t^{8} + 6 t^{5} - 20 t^{2}

7 = - 0.004 x^{2} + 1.15 x + 15

x - 2

\frac{5}{4} \cdot 4

What are the solutions to the equation 5x^2-20x+36=0 ?
The solutions to the equation 5x^2-20x+36=0 are x=2+i(4sqrt(5))/5 ,x=2-i(4sqrt(5))/5
Find the zeros of 5x^2-20x+36=0
The zeros of 5x^2-20x+36=0 are x=2+i(4sqrt(5))/5 ,x=2-i(4sqrt(5))/5